Monday, 18 April 2011

Easter homework

Hope you're all having fun completing the questions!

Here are my answers to the first side of the homework sheet if you want to check your answers - remember we're interested in how you've got to the answers.... not just that you've got the right answer!

Answer sheet

Leave a comment if you need help with any of the questions or want to know how I got my answers...

3 comments:

  1. some help with a2.7

    On A2.7 (a) you have to find the co-ordinates of points A and B. Look at point A first - what do you know about it? Its on the y-axis so ..... x must be equal to 0.

    So if x=0, then 2y = x - 2 should give us the value of y when we put x=0 into it.
    2y = 0 - 2
    2y = -2
    y = -1

    So A has co-ordinates (0,-1)

    Similarly with B, B is on the x-axis so must have y = 0
    Use substitution again 2y = x - 2
    2 x 0 = x - 2
    0 = x - 2
    so x = 2
    Co-ordinates of B are (2,0)

    Gradient of the line 2y = x - 2
    rearrange to find y = x/2 - 2/2
    so y = x/2 - 1
    and the gradient of the line is 1/2 (the co-efficient (number in front) of x)

    c) 2y = x-2 and 2y = x-3
    If you draw these lines on the graph, they will never meet because they are parallel - they have the same gradient - so if the lines never cross that means there is never a solution!

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  2. Q1 - some help on the one on proof

    Think about choosing numbers n-1, n , n+1
    Could be (if n=5), 5-1, 5, 5+1 so 4, 5, 6
    This will always give three consecutive numbers.

    Then think about any three consecutive numbers, there will always be one number that is in the 3 x table.

    eg 1 x 2 x 3 will be a multiple of 3 (because we've x by 3)
    6 x 7 x 8 will be a multiple of 3 (because we've multiplied by a number in the 3 x table).

    The question already gives that n^3 - 1 = n(n-1)(n+1) so must always have a multiple of 3 as one of the consecutive numbers.

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  3. Then if n is odd and bigger than 1.
    We know n(n-1)(n+1) is divisible by 3 (from first part of question)

    If n is odd, n-1 must be even and n+1 must be even. One of them must be in the 4 x table, and the other is not in the 4 x table. So you have a number in the 4xtable x number in 2x table so must have a number in the 8xtable.

    So, its a multiple of 3 and its a multiple of 8. So it must be a multiple of 24.

    Does this help?

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